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I have two strings to compare and the following result should return
s1 = 'toyota innova'
s2 = 'toyota innova 7'
if s1 like s2
return true
OR
s1 = 'tempo traveller'
s2 = 'tempo traveller 15 str' //or tempo traveller 17 str
if s1 like s2
return true
So, how this I compare in python? for eg. getmecab.com/round-trip/delhi/agra/tempo-traveller
In this it is showing that we don't find this model name but if you scroll down there is tempo traveller 12str/15str showing. so I have show these two cabs in search of tempo traveller.
209
Use the in operator for partial matches, i.e., whether one string contains the other string. x in y returns True if x is contained in y ( x is a substring of y ), and False if it is not. If each character of x is contained in y discretely, False is returned.
strcmp is used to compare two different C strings. When the strings passed to strcmp contains exactly same characters in every index and have exactly same length, it returns 0. For example, i will be 0 in the following code: char str1[] = "Look Here"; char str2[] = "Look Here"; int i = strcmp(str1, str2);
Python strings equality can be checked using == operator or __eq__() function. Python strings are case sensitive, so these equality check methods are also case sensitive.
How would you confirm that 2 strings have the same identity? The is operator returns True if 2 names point to the same location in memory. This is what we're referring to when we talk about identity. Don't confuse is with ==, the latter which only tests equality.
You could use in to check if a string is contained in an other:
'toyota innova' in 'toyota innova 7' # True
'tempo traveller' in 'tempo traveller 15 str' # True
If you only want to match the start of the string, you can use str.startswith:
'toyota innova 7'.startswith('toyota innova') # True
'tempo traveller 15 str'.startswith('tempo traveller') # True
Alternatively, if you only want to match the end of the string, you can use str.endswith
'test with a test'.endswith('with a test') # True
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