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public class ByteArr { public static void main(String[] args){ Byte[] a = {(byte)0x03, (byte)0x00, (byte)0x00, (byte)0x00}; Byte[] b = {(byte)0x03, (byte)0x00, (byte)0x00, (byte)0x00}; byte[] aa = {(byte)0x03, (byte)0x00, (byte)0x00, (byte)0x00}; byte[] bb = {(byte)0x03, (byte)0x00, (byte)0x00, (byte)0x00}; System.out.println(a); System.out.println(b); System.out.println(a == b); System.out.println(a.equals(b)); System.out.println(aa); System.out.println(bb); System.out.println(aa == bb); System.out.println(aa.equals(bb)); } } I do not know why all of them print false.
When I run "java ByteArray", the answer is "false false false false".
I think the a[] equals b[] but the JVM is telling me I am wrong, why？？
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A byte in Java is 8 bits. It is a primitive data type, meaning it comes packaged with Java. Bytes can hold values from -128 to 127. No special tasks are needed to use it; simply declare a byte variable and you are off to the races.
equals(byte[] a, byte[] a2) method returns true if the two specified arrays of bytes are equal to one another. Two arrays are equal if they contain the same elements in the same order.
In java automatic type conversion converts any small data type to the larger of the two types. So byte b is converted to int b when you are comparing it with int a . Do know that double is the largest data type while byte is the smallest.
Use Arrays.equals() if you want to compare the actual content of arrays that contain primitive types values (like byte).
System.out.println(Arrays.equals(aa, bb)); Use Arrays.deepEquals for comparison of arrays that contain objects.
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