I have two queries:
select count(*) from my_table where status="accepted"
and
select count(*) from my_table where status="rejected"
I was to find the ratio of accepted/reject so I Was wondering if it's possible to combine the two queries so I don't have to execute two queries
Putting this answer since none offered so far is correct
select count(case when status = "accepted" then 1 end) /
count(case when status = "rejected" then 1 end) as Ratio
from my_table
where status in ("accepted","rejected")
If you also need the individual counts
select count(case when status = "accepted" then 1 end) Accepted,
count(case when status = "rejected" then 1 end) Rejected,
count(case when status = "accepted" then 1 end) /
count(case when status = "rejected" then 1 end) as Ratio
from my_table
where status in ("accepted","rejected")
Note: MySQL does not have a divide by zero problem. It returns NULL when Rejected is 0.
select accepted_count, rejected_count, accepted_count/rejected_count ratio
from (
select sum(CASE WHEN status="accepted" THEN 1 ELSE 0 END) accepted_count,
sum(CASE WHEN status="rejected" THEN 1 ELSE 0 END) rejected_count
from my_table
) A
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