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This is php script that fetches a table values from mysql (one row). & echoes it as JSON
<?php
$username = "user";
$password = "********";
$hostname = "localhost";
$dbh = mysql_connect($hostname, $username, $password) or die("Unable to
connect to MySQL");
$selected = mysql_select_db("spec",$dbh) or die("Could not select first_test");
$query = "SELECT * FROM user_spec";
$result=mysql_query($query);
$outArray = array();
if ($result) {
while ($row = mysql_fetch_assoc($result)) $outArray[] = $row;
}
echo json_encode($outArray);
?>
this is HTML file to receive & print json data.
src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js">
//$('document').ready(function() {
function Preload() {
$.getJSON("http://localhost/conn_mysql.php", function(jsonData){
$.each(jsonData, function(i,j)
{ alert(j.options);});
});}
// });
</script></head>
<body onLoad="Preload()">
</body>
</html> >
274
Your PHP needs to actually put all the rows together:
$query = "SELECT * FROM user_spec";
$result=mysql_query($query);
$outArray = array();
if ($result) {
while ($row = mysql_fetch_assoc($result)) $outArray[] = $row;
}
echo json_encode($outArray);
Your Javascript needs to look at each of the rows..
$.getJSON("/whatever.php", function(jsonData) {
for (var x = 0; x < jsonData.length; x++) {
alert(jsonData[x].options);
}
});
mysql_fetch_assoc will only return a single row from the database. You will need a loop to retrieve all rows:
$data = array();
while ($row = mysql_fetch_assoc($result)) {
// add some or all of $row to the $data array
}
echo json_encode($data);
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