How to click on All links in web page in Selenium WebDriver

Question

I have 10 different pages contain different links. How to click on all the links?

Conditions are : i) I don't know how many links are there ii) I want to count and click on each link

Please suggest me Selenium WebDriver script.

Answer 1

Capture and Navigate all the Links on Webpage

Iterator and advanced for loop can do similar job; However, the inconsistency on page navigation within a loop can be solved using array concept.

private static String[] links = null;
private static int linksCount = 0;

driver.get("www.xyz.com");
List<WebElement> linksize = driver.findElements(By.tagName("a")); 
linksCount = linksize.size();
System.out.println("Total no of links Available: "+linksCount);
links= new String[linksCount];
System.out.println("List of links Available: ");  
// print all the links from webpage 
for(int i=0;i<linksCount;i++)
{
links[i] = linksize.get(i).getAttribute("href");
System.out.println(all_links_webpage.get(i).getAttribute("href"));
} 
// navigate to each Link on the webpage
for(int i=0;i<linksCount;i++)
{
driver.navigate().to(links[i]);
Thread.sleep(3000);
}

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1| Capture all links under specific frame|class|id and Navigate one by one

driver.get("www.xyz.com");  
WebElement element = driver.findElement(By.id(Value));
List<WebElement> elements = element.findElements(By.tagName("a"));
int sizeOfAllLinks = elements.size();
System.out.println(sizeOfAllLinks);
for(int i=0; i<sizeOfAllLinks ;i++)
{
System.out.println(elements.get(i).getAttribute("href"));
}   
for (int index=0; index<sizeOfAllLinks; index++ ) {
getElementWithIndex(By.tagName("a"), index).click();
driver.navigate().back();
}

public WebElement getElementWithIndex(By by, int index) {
WebElement element = driver.findElement(By.id(Value));
List<WebElement> elements = element.findElements(By.tagName("a")); 
return elements.get(index);
}

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2| Capture all links [Alternate method]

Java

driver.get(baseUrl + "https://www.google.co.in");
List<WebElement> all_links_webpage = driver.findElements(By.tagName("a")); 
System.out.println("Total no of links Available: " + all_links_webpage.size());
int k = all_links_webpage.size();
System.out.println("List of links Available: ");
for(int i=0;i<k;i++)
{
if(all_links_webpage.get(i).getAttribute("href").contains("google"))
{
String link = all_links_webpage.get(i).getAttribute("href");
System.out.println(link);
}   
}

Python

from selenium import webdriver

driver = webdriver.Firefox()
driver.get("https://www.google.co.in/")
list_links = driver.find_elements_by_tag_name('a')

for i in list_links:
        print i.get_attribute('href')

driver.quit()

Answer 2

public static void main(String[] args) 
    {
        FirefoxDriver fd=new FirefoxDriver();
        fd.get("http:www.facebook.com");
        List<WebElement> links=fd.findElements(By.tagName("a"));
        System.out.println("no of links:" +links.size());

        for(int i=0;i<links.size();i++)
        {
            if(!(links.get(i).getText().isEmpty()))
            {
            links.get(i).click();
            fd.navigate().back();
            links=fd.findElements(By.tagName("a"));
            }       
        }
   }

This program clicks on a link, navigates back to the page and clicks the second link again.