I have a script that runs every 15 minutes but sometimes if the box is busy it hangs and the next process will start before the first one is finished creating a snowball effect. How can I add a couple lines to the bash script to check to see if something is running first before starting?
To check the exit code we can simply print the $? special variable in bash. This variable will print the exit code of the last run command.
Bash commands to check running process: pgrep command – Looks through the currently running bash processes on Linux and lists the process IDs (PID) on screen. pidof command – Find the process ID of a running program on Linux or Unix-like system.
Extracting the elusive exit code To display the exit code for the last command you ran on the command line, use the following command: $ echo $? The displayed response contains no pomp or circumstance. It's simply a number.
You can use pidof -x
if you know the process name, or kill -0
if you know the PID.
Example:
if pidof -x vim > /dev/null
then
echo "Vim already running"
exit 1
fi
Why don't set a lock file ?
Something like
yourapp.lock
Just remove it when you process is finished, and check for it before to launch it.
It could be done using
if [ -f yourapp.lock ]; then
echo "The process is already launched, please wait..."
fi
In lieu of pidfiles, as long as your script has a uniquely identifiable name you can do something like this:
#!/bin/bash
COMMAND=$0
# exit if I am already running
RUNNING=`ps --no-headers -C${COMMAND} | wc -l`
if [ ${RUNNING} -gt 1 ]; then
echo "Previous ${COMMAND} is still running."
exit 1
fi
... rest of script ...
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