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Hoping for something more elegant than
if (i>0 && i<100) 
846
If x is in range, then it must be greater than or equal to low, i.e., (x-low) >= 0. And must be smaller than or equal to high i.e., (high – x) <= 0. So if result of the multiplication is less than or equal to 0, then x is in range.
ValueRange. of(minValue, maxValue); range. isValidIntValue(x); it returns true if minValue <= x <= MaxValue - i.e. within the range.
You could add spacing ;)
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