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I'm looking for a way to get a list of files that match a pattern (pref regex) in a given directory.
I've found a tutorial online that uses apache's commons-io package with the following code:
Collection getAllFilesThatMatchFilenameExtension(String directoryName, String extension) { File directory = new File(directoryName); return FileUtils.listFiles(directory, new WildcardFileFilter(extension), null); } But that just returns a base collection (According to the docs it's a collection of java.io.File). Is there a way to do this that returns a type safe generic collection?
558
list() returns the array of files and directories in the directory defined by this abstract path name. The method returns null, if the abstract pathname does not denote a directory.
walk to walk a file tree and stream operation filter to find files that match a specific file extension from a folder and its subfolders. try (Stream<Path> walk = Files. walk(Paths. get("C:\\test"), 1)) { //... }
From the Window's Start button, select "Search". Select "All files and folders" on the left. In the pop-up window, type in the file name (with . java properly) in "All or part of the file name".
See File#listFiles(FilenameFilter).
File dir = new File("."); File [] files = dir.listFiles(new FilenameFilter() { @Override public boolean accept(File dir, String name) { return name.endsWith(".xml"); } }); for (File xmlfile : files) { System.out.println(xmlfile); } Since Java 8 you can use lambdas and achieve shorter code:
File dir = new File(xmlFilesDirectory); File[] files = dir.listFiles((d, name) -> name.endsWith(".xml")); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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