How to check if 3 sides form a triangle in C++

Question

I am trying to check if 3 sides form a triangle in C++, but the answer for all possible numbers I tried it says wrong...

#include <iostream>
#include <cmath>

using namespace std;

int main()
{
    int a, b, c;

    cin >> a >> b >> c;

    if (pow(a,2) == pow(b,2) * pow(c,2) || pow(b,2) == pow(a,2) * pow(c,2) || pow(c,2) == pow(a,2) * pow(b,2))
        cout << "The sides form a triangle" << endl;
    else
        cout << "The sides do not form a triangle." << endl;
    return 0;
}

Answer 1

Let's say that a, b, c is the sides of the triangle. Therefore, it must be satisfy this criteria :

1. a + b > c
2. a + c > b
3. b + c > a

All the criteria must be true. If one of them are false, then a, b, c will not create the triangle.

#include <iostream>
#include <cmath>

using namespace std;

int main()
{
    int a, b, c;
    cin >> a >> b >> c;
    // check whether a, b, c can form a triangle
    if (a+b > c && a+c > b && b+c > a)
        cout << "The sides form a triangle" << endl;
    else
        cout << "The sides do not form a triangle." << endl;
    return 0;
}