Can I override only one method in inheritence?

Question

My C++ code is as follows:

#include<iostream>
using namespace std;

class A
{
    public:
        virtual void f(int i)
        {
            cout << "A's f(int)!" << endl;
        }
        void f(int i, int j)
        {
            cout << "A's f(int, int)!" << endl;
        }
};

class B : public A
{
    public:
        virtual void f(int i)
        {
            cout << "B's f(int)!" << endl;
        }
};

int main()
{
    B b;
    b.f(1,2);
    return 0;
}

during compilation I get:

g++ -std=c++11 file.cpp 
file.cpp: In function ‘int main()’:
file.cpp:29:9: error: no matching function for call to ‘B::f(int, int)’
file.cpp:29:9: note: candidate is:
file.cpp:20:16: note: virtual void B::f(int)
file.cpp:20:16: note:   candidate expects 1 argument, 2 provided

When I tried to use override after B's f(int), I got the same error.

Is it possible in C++ to override only 1 method? I've been searching for a code example using override that will compile on my machine and haven't found one yet.

Answer 1

The problem is that your virtual function f() in class B hides A's non-virtual overload with an identical name. You can use a using declaration to bring it into scope:

class B : public A
{
    public:
        using A::f;
    //  ^^^^^^^^^^^

        virtual void f(int i)
        {
            cout << "B's f(int)!" << endl;
        }
};