Is there a simple way to check the type of an object? I need something along the following lines:
MyObject^ mo = gcnew MyObject();
Object^ o = mo;
if( o->GetType() == MyObject )
{
// Do somethine with the object
}
else
{
// Try something else
}
At the moment I'm using nested try-catch blocks looking for System::InvalidCastException
s which feels ugly but works. I was going to try and profile something like the code above to see if it's any faster/slower/readable but can't work out the syntax to even try.
In case anyone's wondering, this comes from having a single queue entering a thread which supplied data to work on. Occasionally I want to change settings and passing them in via the data queue is a simple way of doing so.
To determine whether an object is a specific type, you can use your language's type comparison keyword or construct.
C++ has no direct method to check one object is an instance of some class type or not. In Java, we can get this kind of facility. In C++11, we can find one item called is_base_of<Base, T>. This will check if the given class is a base of the given object or not.
You can use MyObject::typeid
in C++/CLI the same way as typeof(MyObject)
is used in C#. Code below shamelessly copied from your question and modified ...
MyObject^ mo = gcnew MyObject();
Object^ o = mo;
if( o->GetType() == MyObject::typeid )
{
// Do somethine with the object
}
else
{
// Try something else
}
You should check out How to: Implement is and as C# Keywords in C++:
This topic shows how to implement the functionality of the is and as C# keywords in Visual C++.
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