I have a list:
ab = [1, 2, a, b, c]
I did:
strab = str(ab).
So strab
is now a string.
I want to cast that string back into a list.
How can I do that?
The easiest and safest way would be to use ast.literal_eval()
:
import ast
ab = [1, 2, 'a', 'b', 'c'] # a list
strab = str(ab) # the string representation of a list
strab
=> "[1, 2, 'a', 'b', 'c']"
lst = ast.literal_eval(strab) # convert string representation back to list
lst
=> [1, 2, 'a', 'b', 'c']
ab == lst # sanity check: are they equal?
=> True # of course they are!
Notice that calling eval()
also works, but it's not safe and you should not use it:
eval(strab)
=> [1, 2, 'a', 'b', 'c']
Use the ast package:
import ast
lst = ast.literal_eval(strab)
In the context of setting a numpy array element with a sequence, you can use the built-in join to bypass setting it to a string:
str_list_obj = '-'.join(list_obj)
and afterwards when needed split the string sequence again with the same connector (provided it does not appear in the list's strings):
og_list_obj = str_list_obj.split("-")
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