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In C and C++ you can tell the compiler that a number is a 'long' by putting an 'l' at the end of the number. e.g long x = 0l;
How can I tell the C# compiler that a number is a byte?
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Basically, to do a bit to byte conversion, you take an 8 bit binary number and form it into groups of 4 bits (nibbles). You then translate each nibble into a hexadecimal number (a 2 hex digit byte) using this table. You then multiply the left digit by 16 and add the result to the first digit.
An int value can be converted into bytes by using the method int. to_bytes().
Solution 1. int intValue = 2; byte byteValue = Convert. ToByte(intValue);
In Java, there are two types of casting: Widening Casting (automatically) - converting a smaller type to a larger type size. byte -> short -> char -> int -> long -> float -> double. Narrowing Casting (manually) - converting a larger type to a smaller size type. double -> float -> long -> int -> char -> short -> byte.
A byte is not just 8 values between 0 and 1, but 256 (28) different combinations (rather permutations) ranging from 00000000 via e.g. 01010101 to 11111111 . Thus, one byte can represent a decimal number between 0(00) and 255. Puzzled?
byte b = (byte) 123;
even though
byte b = 123;
does the same thing. If you have a variable:
int a = 42;
byte b = (byte) a;
According to the C# language specification there is no way to specify a byte literal. You'll have to cast down to byte in order to get a byte. Your best bet is probably to specify in hex and cast down, like this:
byte b = (byte) 0x10;
Remember, if you do:
byte b = (byte)300;
it's not going to work the way you expect.
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