Menu
If I have
public class AImplementation:IAInterface { void IAInterface.AInterfaceMethod() { } void AnotherMethod() { ((IAInterface)this).AInterfaceMethod(); } } How to call AInterfaceMethod() from AnotherMethod() without explicit casting?
587
The following is an example of how to call "Explicit Interface Method" in the same class using class methods. Output: Class1 Display Method. Iinterface_1 Method Explicit interface implementation. Iinterface_1 Method Implicit interface implementation.
An implementing class is free to mark any or all of the methods that implement the interface as virtual. Derived classes can override or provide new implementations.
In order to call the methods using interface reference(here r is interface reference), you have to assign to class object to it. Like if you are assigning Person1's object obj1 to r i.e. r = obj1; then you call the Speed() and Distance() methods that are implemented by the Person1 class.
Resolving conflicts here ..... "Implicit Implementation" - means just simple implementation of a particular method having same name and same signature which belongs to the same class itself, where as "Explicit Implementation" - means implementation of a method using their Interface name having same name and signature ...
A number of answers say that you cannot. They are incorrect. There are lots of ways of doing this without using the cast operator.
Technique #1: Use "as" operator instead of cast operator.
void AnotherMethod() { (this as IAInterface).AInterfaceMethod(); // no cast here } Technique #2: use an implicit conversion via a local variable.
void AnotherMethod() { IAInterface ia = this; ia.AInterfaceMethod(); // no cast here either } Technique #3: write an extension method:
static class Extensions { public static void DoIt(this IAInterface ia) { ia.AInterfaceMethod(); // no cast here! } } ... void AnotherMethod() { this.DoIt(); // no cast here either! } Technique #4: Introduce a helper:
private IAInterface AsIA => this; void AnotherMethod() { this.AsIA.IAInterfaceMethod(); // no casts here! } You can introduce a helper private property:
private IAInterface IAInterface => this; void IAInterface.AInterfaceMethod() { } void AnotherMethod() { IAInterface.AInterfaceMethod(); } If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
