How to call constructor if function has the same name

Question

If I have the following:

class T
{
   public: 
      T(){}
};

void T()
{
}

int main()
{
  T(); // this calls the function, how can I call the constructor T()?
}

I have no any issue with it, since I could be possible to rename it, but just curious how I could force it to call the constructor, and also I am asking to myself why the function call seems to have higher priority than the constructor. Additionally, why is there no warning message in regards of the duplicate name.

Answer 1

Besides what jaunchopanza said, you can qualify the call:

T::T();

With this version, you can create temporaries:

class T
{
   public: 
      T(){}
};

void foo(T) {}

void T()
{
}

int main(){
   foo(T::T());
}