I have two nested lists with the same structure that I'd like to combine (in the c() sense).
There might already exist a concept for what I mean by same structure in graph theory, or in computer science, for this relationship but I am not aware.
So here is my attempt to clarify what I mean by same structure:
So I am wondering if there is already a solution for this problem which I feel might be rather general and common...(?) Any solution involving:
rapply;purrr functions;rlist packagewould be great!
foo and bar are two example lists with same structure.
wonderful is the desired list that results from combining foo and bar (done manually).
I hope it is clear enough!
# Input lists: foo and bar
foo <- list(a = list(a1 = 1:3, a2 = rep('a', 3)), b = list(b1 = list(b11 = c(4,5,6), b12 = rep('b', 3)), b2 = list(b21 = list(b31 = c(0, 1, 2)))), c = list(list(c21 = 1:3), list(c21 = 4:6), list(c21 = 7:9)))
bar <- list(a = list(a1 = 1:3, a2 = rep('z', 3)), b = list(b1 = list(b11 = c(-1,2,5), b12 = rep('b', 3)), b2 = list(b21 = list(b31 = -c(1,2,3)))), c = list(list(c21 = 3:1), list(c21 = 5:3)))
# wonderful: desired list (result from combining foo and bar)
wonderful <- list(
  a = list(
    a1 = c(foo$a$a1, bar$a$a1), 
    a2 = c(foo$a$a2, bar$a$a2)
    ),
  b = list(
    b1 = list(
      b11 = c(foo$b$b1$b11, bar$b$b1$b11),
      b12 = c(foo$b$b1$b12, bar$b$b1$b12)
      ),
    b2 = list(
      b21 = list(
        b31 = c(foo$b$b2$b21$b31, bar$b$b2$b21$b31)
        )
      )
    ),
  c = c(foo$c, bar$c)
)
str(foo)
#> List of 3
#>  $ a:List of 2
#>   ..$ a1: int [1:3] 1 2 3
#>   ..$ a2: chr [1:3] "a" "a" "a"
#>  $ b:List of 2
#>   ..$ b1:List of 2
#>   .. ..$ b11: num [1:3] 4 5 6
#>   .. ..$ b12: chr [1:3] "b" "b" "b"
#>   ..$ b2:List of 1
#>   .. ..$ b21:List of 1
#>   .. .. ..$ b31: num [1:3] 0 1 2
#>  $ c:List of 3
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 1 2 3
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 4 5 6
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 7 8 9
str(bar)
#> List of 3
#>  $ a:List of 2
#>   ..$ a1: int [1:3] 1 2 3
#>   ..$ a2: chr [1:3] "z" "z" "z"
#>  $ b:List of 2
#>   ..$ b1:List of 2
#>   .. ..$ b11: num [1:3] -1 2 5
#>   .. ..$ b12: chr [1:3] "b" "b" "b"
#>   ..$ b2:List of 1
#>   .. ..$ b21:List of 1
#>   .. .. ..$ b31: num [1:3] -1 -2 -3
#>  $ c:List of 2
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 3 2 1
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 5 4 3
str(wonderful)
#> List of 3
#>  $ a:List of 2
#>   ..$ a1: int [1:6] 1 2 3 1 2 3
#>   ..$ a2: chr [1:6] "a" "a" "a" "z" ...
#>  $ b:List of 2
#>   ..$ b1:List of 2
#>   .. ..$ b11: num [1:6] 4 5 6 -1 2 5
#>   .. ..$ b12: chr [1:6] "b" "b" "b" "b" ...
#>   ..$ b2:List of 1
#>   .. ..$ b21:List of 1
#>   .. .. ..$ b31: num [1:6] 0 1 2 -1 -2 -3
#>  $ c:List of 5
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 1 2 3
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 4 5 6
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 7 8 9
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 3 2 1
#>   ..$ :List of 1
#>   .. ..$ c21: int [1:3] 5 4 3
                Here's a go at it:
library(purrr)
rec_map <- function(fizz, buzz) {
  if(is.atomic(fizz) | is.null(names(fizz))){
    c(fizz, buzz)
  } else {
    imap(fizz,
         ~rec_map(fizz[[.y]], buzz[[.y]]))
  }
}
temp <- rec_map(foo, bar)
all.equal(temp, wonderful)
#> [1] TRUE
I'm by no means a computer scientist, so take the solution with a grain of salt. I am not certain about the behavior desired when there are no names for one level, but then one level down there are names (e.g., foo$c). So I just combined the results (c()) if we encountered a level without names.
prec_map <- function(...){
  dots <- list(...)
  first_el = dots[[1]]
  if(is.atomic(first_el) | is.null(names(first_el))){
    do.call(c, dots)
  } else {
    imap(first_el,
         function(el, nme){
           one_level_down <- map(dots, nme)
           do.call(prec_map, one_level_down)
         })
  }
}
temp <- prec_map(foo, bar)
all.equal(temp, wonderful)
[1] TRUE
I haven't tested it out thoroughly, but light testing looks like it gets the job done.
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