How to avoid short-circuited evaluation in JavaScript?

Question

I need to execute both sides of an && statement, but this won't happen if the first part returns false. Example:

function doSomething(x) {
    console.log(x);
}

function checkSomething(x) {
    var not1 = x !== 1;
    if (not1) doSomething(x);

    return not1;
}

function checkAll() {
    return checkSomething(1)
        && checkSomething(3)
        && checkSomething(6)
}

var allValid = checkAll(); // Logs nothing, returns false

The problem here is that doSomething(x) should log 3 and 6, but because checkSomething(1) returns false, the other checks won't be called. What is the easiest way to run all the checks and return the result?

I know I could save all the values in variables and check those subsequently, but that does not look very clean when I have a lot of checks. I am looking for alternatives.

Answer 1

Use a single &. That is a bitwise operator. It will execute all conditions and then return a bitwise sum of the results.

 function checkAll() {
    return checkSomething(1)
      & checkSomething(2)
      & checkSomething(3)
 }

Answer 2

You can multiply the comparison result and cast it to boolean.

function checkSomething(x) {
    var not1 = x !== 1;
    if (not1) alert(x);
    return not1;
}

function checkAll() {
    return !!(checkSomething(1) * checkSomething(2) * checkSomething(3));
}

document.write(checkAll());

Or take some array method:

function checkAll() {
    return [checkSomething(2), checkSomething(2), checkSomething(3)].every(Boolean);
}