How to @Autowire objects in Validator classes?

Question

Is it possible to Autowire an object in a Validation class? I keep getting null for the object that is supposed to be Autowired...

Answer 1

Are your Validation class an enabled Spring bean ??? If not, you always will get null for your object autowired. Make sure you have enabled your Validation class.

And do not forget enable The Annotation config bean post-processor (see <context:annotation-config /> element)

<beans xmlns="http://www.springframework.org/schema/beans" 
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
                           http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
                           http://www.springframework.org/schema/context
                           http://www.springframework.org/schema/context/spring-context-2.5.xsd">
    <context:annotation-config />
</beans>

How to enable your Validation class as a managed Spring bean. Either

1° By using xml (As shown above)

<beans ...>
    <bean class="AccessRequestValidator"/>
    <context:annotation-config />
</beans>

2° By using annotation instead (Notice @Component just above class)

@Component
public class AccessRequestValidator implements Validator {

}

But to enable Spring annotated component scanning, you must enable a bean-post processor (notice <context:component-scan element)

<beans ...>
    <context:annotation-config />
    <context:component-scan base-package="<PUT_RIGHT_HERE_WHICH_ROOT_PACKAGE_SHOULD_SPRING_LOOK_FOR_ANY_ANNOTATED_BEAN>"/>
</beans>

Inside your Controller, just do it (Do not use new operator)

Choose one of the following strategies

public class MyController implements Controller {

    /**
      * You can use FIELD @Autowired
      */
    @Autowired
    private AccessRequestValidator accessRequestValidator;

    /**
      * You can use PROPERTY @Autowired
      */
    private AccessRequestValidator accessRequestValidator;
    private @Autowired void setAccessRequestValidator(AccessRequestValidator accessRequestValidator) {
        this.accessRequestValidator = accessRequestValidator;
    }

    /**
      * You can use CONSTRUCTOR @Autowired
      */
    private AccessRequestValidator accessRequestValidator;

    @Autowired
    public MyController(AccessRequestValidator accessRequestValidator) {
        this.accessRequestValidator = accessRequestValidator;
    }   

}

UPDATE

Your web app structure should looks like

<CONTEXT-NAME>/
       WEB-INF/
           web.xml
           <SPRING-SERVLET-NAME>-servlet.xml
           business-context.xml
           classes/
               /com
                   /wuntee
                       /taac
                           /validator
                               AccessRequestValidator.class
           lib/
               /**
                 * libraries needed by your project goes here
                 */

Your web.xml should looks like (NOTICE contextConfigLocation context-param and ContextLoaderListener)

<web-app version="2.4" 
    xmlns="http://java.sun.com/xml/ns/j2ee" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee
                       http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <!--If your business-context.xml lives in the root of classpath-->
        <!--replace by classpath:business-context.xml-->
        <param-value>
            /WEB-INF/business-context.xml
        </param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <servlet>
        <servlet-name><SPRING-SERVLET-NAME></servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name><SPRING-SERVLET-NAME></servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>
</web-app>

Your <SPRING-SERVLET-NAME>-servlet.xml should looks like (Notice i am using Spring 2.5 - replace if you are using 3.0)

 <beans xmlns="http://www.springframework.org/schema/beans" 
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
                           http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
                           http://www.springframework.org/schema/context
                           http://www.springframework.org/schema/context/spring-context-2.5.xsd">
    <!--ANY HANDLER MAPPING-->
    <!--ANY VIEW RESOLVER-->
    <context:component-scan base-package="com.wuntee.taac"/>
    <context:annotation-config/>
</beans>