How to assign an output to a shellscript variable?

Question

How to assign this result to a shell variable?

Input:

echo '1+1' | bc -l

Output:

2

Attempts:

(didn't work)

#!bin/sh a=echo '1+1' | bc -l echo $a 

Answer 1

You're looking for the shell feature called command-substitution.

There are 2 forms of cmd substitution

1. Original, back to the stone-age, but completely portable and available in all Unix-like shells (well almost all).

   You enclose your value generating commands inside of the back-ticks characters, i.e.

   $ a=`echo 1+1 | bc -l` $ echo $a 2 $ 

2. Modern, less clunky looking, easily nestable cmd-substitution supplied with $( cmd ), i.e.

   $ a=$(echo 1+1 |  bc -l) $ echo $a 2 $ 

Your 'she-bang' line says, #!/bin/sh, so if you're running on a real Unix platform, then it's likely your /bin/sh is the original Bourne shell, and will require that you use option 1 above.

If you try option 2 while still using #!/bin/sh and it works, then you have modern shell. Try typing echo ${.sh.version} or /bin/sh -c --version and see if you get any useful information. If you get a version number, then you'll want to learn about the extra features that newer shells contain.

Speaking of newer features, if you are really using bash, zsh, ksh93+, then you can rewrite your sample code as

a=$(( 1+1 )) 

Or if you're doing more math operations, that would all stay inside the scope, you can use shell feature arithmetic like:

(( b=1+1 )) echo $b 2 

In either case, you can avoid extra process creation, but you can't do floating point arithmetic in the shell (whereas you can with bc).