Problem: return all records where
Jon Doe
=<bus_contact>
OR <bus_sponsor>
.
Current code returns record 1, so what modifications are required to return records 1 and 2 using just one query?.
XML
<root>
<row>
<project_id>1</project_id>
<project_name>Name1</project_name>
<bus_contact>Jon Doe</bus_contact>
<bus_sponsor>Bruce Wayne</bus_sponsor>
</row>
<row>
<project_id>2</project_id>
<project_name>Name2</project_name>
<bus_contact>Peter Parker</bus_contact>
<bus_sponsor>Jon Doe</bus_sponsor>
</row>
</root>
C#
class Program
{
static void Main (string[] args)
{
XElement main = XElement.Load ("master_list.xml");
var results = main.Descendants ("row")
.Descendants ("bus_contact")
.Where (e => e.Value == "Jon Doe")
.Select (e => e.Parent)
.Select (e => new {
project_id = e.Descendants ("project_id").FirstOrDefault ().Value,
project_name = e.Descendants ("project_name").FirstOrDefault ().Value
});
foreach (var result in results)
Console.WriteLine ("{0}, {1}", result.project_id, result.project_name);
Console.ReadLine ();
}
}
Edit : This is not exactly the same problem as pointed out in the possible duplicate link. Yes, it partially refers to that but as a beginner getting an answer with appropriate context, which the accepted answer provides, is quite helpful.
Use ||
in combination with Any
, like this:
var results = main.Descendants("row")
.Where(r =>
r.Descendants("bus_contact").Any(c => c.Value == "Jon Doe")
|| r.Descendants("bus_sponsor").Any(c => c.Value == "Jon Doe")
);
Using Any
lets you query by a condition on a child, without actually descending to the child level. This eliminated necessity to climb the tree back by selecting Parent
.
If each row
element has only one subelement item of each kind (bus_contact
, bus_sponsor
, etc.) you can simplify the whole query by using Element
method instead of Descendants
var results =
main.Descendants ("row")
.Where (r => r.Element("bus_contact").Value == "Jon Doe"
|| r.Element("bus_contact").Value == "Jon Doe")
.Select (r => new {
project_id = r.Element("project_id").Value,
project_name = r.Element("project_name").Value
});
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