How to add call back for $resource methods in AngularJS

Question

It could be a common case that we need to show an error/success message to the user after he updates/creates some data, how can we implement it in AngularJS?
I want to add callbacks but could not find a solution. Using $http.post().success().error() works, but I wonder if I can do it with the higher lever API $resource.
Or, we should write directives or use $watch()?
Thanks for your help in advance.

Answer 1

Actions from the Resource class can be passed success and error callbacks just like the lower level $http service

From the docs

• HTTP GET "class" actions: Resource.action([parameters], [success], [error])
• non-GET "class" actions: Resource.action([parameters], postData, [success], [error])

Non-get actions are prefixed with $.

So you can do this

User.get({userId:123}, function(u, getResponseHeaders){   // this is get's success callback   u.abc = true;   u.$save(function(u, putResponseHeaders) {     // This is $save's success callback, invoke notification from here   }); }); 

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Edit: here's another example from a previous plunker. The get request will fail since it request a non existing json file. The error callback will be run.

someResource.get(function(data){     console.log('success, got data: ', data);        }, function(err){     alert('request failed'); }); 

Answer 2

With latest AngularJS versions, you could have a look to the $interceptors which are part of the $httpProvider.

Then you can intercept ALL the requests before beeing sent or after the response.

angular.module('app').config(function($httpProvider){    $httpProvider.interceptors.push(function($q) {     return {       'request': function(config) {         console.log('I will send a request to the server');         return config;        },        'response': function(response) {         // called if HTTP CODE = 2xx          console.log('I got a sucessfull response from server');          return response;       }        'responseError': function(rejection) {         // called if HTTP CODE != 2xx         console.log('I got an error from server');         return $q.reject(rejection);       }     };   });  }); 

Note that you have to return config or response to get it working.

In the case of rejection, you need to return a deferred rejection, to get the $http.get().error() still working after the interception.