Find out if resource is used

Question

I am looking for an efficient way to find out if a resource (mostly a drawable) is used in Java or in an XML file.

The problem is, that on my current project the drawables are changed often and now I have some drawables, which might never be used.

Is there a tool/way to find those unused drawables without search each filename in the whole project?

Answer 1

I wrote a tool based on python to solve this problem. As this is not the place to share it directly, I created a project page which is now offline.

UPDATE:
The development has stopped since Lint can do the same and is already included in the Android SDK.

Answer 2

I just wrote this bash script just for fun:

PROJECT="/path/to/the/project" for file in $(ls $PROJECT/res/drawable -l | awk '{ print $8}' | sed 's/\..\+//g'); do count=0; for SRCFILE in `find $PROJECT -name "*.xml" -print 2> /dev/null`; do let "count+=$(grep -c @drawable/$file $SRCFILE)"; done; for SRCFILE in `find $PROJECT -name "*.java" -print 2> /dev/null`; do let "count+=$(grep -c R.drawable.$file $SRCFILE)"; done; if [ $count -lt 1 ]; then echo -e "\e[0;31m$file\e[0m not used"; else echo -e "\e[0;32m$file\e[0m used"; fi; done;  

It works fine, though I'm a bash newbie so it can be highly improved:

It searches drawables resources only (@drawable/name on the XML files, and R.drawable.name on the Java files).

By the way, I didn't know that boxscore and calendarlogos were not being used in my project. Another funny fact is that most users don't use Linux, so this won't help too many people.

---

For MacOs would be something like this:

PROJECT="/path/to/the/project" for file in $(ls -l $PROJECT/res/drawable | awk '{ print $9}' | sed 's/\..\+//g'); do count=0; for SRCFILE in `find $PROJECT -name "*.xml" -print 2> /dev/null`; do let "count+=$(grep -c @drawable/$file $SRCFILE)"; done; for SRCFILE in `find $PROJECT -name "*.java" -print 2> /dev/null`; do let "count+=$(grep -c R.drawable.$file $SRCFILE)"; done; if [ $count -lt 1 ]; then echo -e "$file not used"; else echo -e "$file used"; fi; done;