How to add two numpy arrays to a dictionary in python ?
a = [[1]
     [3]]
b = [array([[[ 41.,  179.],
             [ 451.,  254.],
             [ 449.,  10.],
             [ 53.,  256.]]], dtype=float32), array([[[ 181.,  313.],
             [  27.,  24.],
             [ 113.,  192.],
             [ 08.,  20.]]], dtype=float32)]
I wish to display a and b as
c = {1: array([[ 41.,  179.],
            [ 451.,  254.],
            [ 449.,  10.],
            [ 53.,  256.]], dtype=float32),
     3: array([[ 181.,  313.],
           [  27.,  24.],
           [ 113.,  192.],
           [ 08.,  20.]], dtype=float32)}
                c = dict(zip(a[:,0], b)) would turn your a and b variables into a dictionary. I'm not sure whether that's what you're looking for, though.
Using a dictionary comprehension:
I assume you meant to define a as:
a = [1, 3]
then you can get c with:
c = {e: b[i] for i, e in enumerate(a)}
which gives the intended output of:
{1: array([[[  41.,  179.],
    [ 451.,  254.],
    [ 449.,   10.],
    [  53.,  256.]]], dtype=float32),
 3: array([[[ 181.,  313.],
    [  27.,   24.],
    [ 113.,  192.],
    [   8.,   20.]]], dtype=float32)}
If you actually only have a as a list of an element as in [[1], [3]], you can do:
a = [i[0] for i in a]
#[[1], [3]] --> [1, 3]
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