I'll ask this with a Scala example, but it may well be that this affects other languages which allow hybrid imperative and functional styles.
Here's a short example (UPDATED, see below):
def method: Iterator[Int] {
// construct some large intermediate value
val huge = (1 to 1000000).toList
val small = List.fill(5)(scala.util.Random.nextInt)
// accidentally use huge in a literal
small.iterator filterNot ( huge contains _ )
}
Now iterator.filterNot
works lazily, which is great! As a result, we'd expect that the returned iterator won't consume much memory (indeed, O(1)). Sadly, however, we've made a terrible mistake: since filterNot
is lazy, it keeps a reference to the function literal huge contains _
.
Thus while we thought that the method would require a large amount of memory while it was running, and that that memory could be freed up immediately after the termination of the method, in fact that memory is stuck until we forget the returned Iterator
.
(I just made such a mistake, which took a long time to track down! You can catch such things looking at heap dumps ...)
What are best practices for avoiding this problem?
It seems that the only solution is to carefully check for function literals which survive the end of the scope, and which captured intermediate variables. This is a bit awkward if you're constructing a non-strict collection and planning on returning it. Can anyone think of some nice tricks, Scala-specific or otherwise, that avoid this problem and let me write nice code?
UPDATE: the example I'd given previously was stupid, as huynhjl's answer below demonstrates. It had been:
def method: Iterator[Int] {
val huge = (1 to 1000000).toList // construct some large intermediate value
val n = huge.last // do some calculation based on it
(1 to n).iterator map (_ + 1) // return some small value
}
In fact, now that I understand a bit better how these things work, I'm not so worried!
When the execution of the function terminates (returns), the local variables are destroyed.
A scope is a region of the program and broadly speaking there are three places, where variables can be declared: Inside a function or a block which is called local variables, In the definition of function parameters which is called formal parameters. Outside of all functions which is called global variables.
At any given time during execution, you'll have at most four active Python scopes—local, enclosing, global, and built-in—depending on where you are in the code. On the other hand, you'll always have at least two active scopes, which are the global and built-in scopes.
A variable created in the main body of the Python code is a global variable and belongs to the global scope. Global variables are available from within any scope, global and local.
Are you sure you're not oversimplifying the test case? Here is what I run:
object Clos {
def method: Iterator[Int] = {
val huge = (1 to 2000000).toList
val n = huge.last
(1 to n).iterator map (_ + 1)
}
def gc() { println("GC!!"); Runtime.getRuntime.gc }
def main(args:Array[String]) {
val list = List(method, method, method)
list.foreach(m => println(m.next))
gc()
list.foreach(m => println(m.next))
list.foreach(m => println(m.next))
}
}
If I understand you correctly, because main
is using the iterators even after the gc()
call, the JVM would be holding onto the huge
objects.
This is how I run it:
JAVA_OPTS="-verbose:gc" scala -cp classes Clos
This is what it prints towards the end:
[Full GC 57077K->57077K(60916K), 0.3340941 secs]
[Full GC 60852K->60851K(65088K), 0.3653304 secs]
2
2
2
GC!!
[Full GC 62959K->247K(65088K), 0.0610994 secs]
3
3
3
4
4
4
So it looks to me as if the huge
objects were reclaimed...
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