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By using an online tool and wikipedia I found out that every sha-256 encrypted string is 64 chars longs containing numbers and characters. Hence I assumed that there are 34^36 combinations ( 2^216 simplified by an algebra calculator ). After doing some research I found out that most people said there are 2^256 combinations. Could someone explain ? To make the context clear, I write a paper about cryptocurrencies and try to explain how many different combinations there are to encrypt and how long this could take ( therefore how many guesses it could take) and compare this to the amount of total atoms in the universe (roughly 10^85).
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SHA-256 – SHA-256 results in a 256-bit hash and has a 512-bit block size. The message input is processed in 32-bit words, while the initialization variables and constants are also 32 bits in length. SHA-256 also involves 64 rounds. SHA-384 – This version produces a 384-bit hash.
There is technically a limit, but it's quite large. The padding scheme used for SHA-256 requires that the size of the input (in bits) be expressed as a 64-bit number. Therefore, the maximum size is (264-1)/8 bytes ~= 2'091'752 terabytes. That renders the limit almost entirely theoretical, not practical.
SHA-256 produces 256 bits which is 32 bytes, not characters, each byte has 256 possible values.
There are 256 bits and each bit has 2 values (0 or 1), thus 2^256.
There are 32 bytes and each byte has 256 values, thus 256^32.
Note: 2^256 == 256^32 ~= 10^77.
The 32 bytes can be encoded many ways, in hexadecimal it would be 64 characters, in Base64 it would be 44 characters.
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Total combinations of SHA-256 is
115,792,089,237,316,195,423,570,985,008,687,907,853,269,984,665,640,564,039,457,584,007,913,129,639,936
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