How is Python's glob.glob ordered?

Question

Order is arbitrary, but you can sort them yourself

If you want sorted by name:

sorted(glob.glob('*.png'))

sorted by modification time:

import os
sorted(glob.glob('*.png'), key=os.path.getmtime)

sorted by size:

import os
sorted(glob.glob('*.png'), key=os.path.getsize)

etc.

It is probably not sorted at all and uses the order at which entries appear in the filesystem, i.e. the one you get when using ls -U. (At least on my machine this produces the same order as listing glob matches).

By checking the source code of glob.glob you see that it internally calls os.listdir, described here:

http://docs.python.org/library/os.html?highlight=os.listdir#os.listdir

Key sentence: os.listdir(path) Return a list containing the names of the entries in the directory given by path. The list is in arbitrary order. It does not include the special entries '.' and '..' even if they are present in the directory.

Arbitrary order. :)

Order is arbitrary, but there are several ways to sort them. One of them is as following:

#First, get the files:
import glob
import re
files =glob.glob1(img_folder,'*'+output_image_format)
# if you want sort files according to the digits included in the filename, you can do as following:
files = sorted(files, key=lambda x:float(re.findall("(\d+)",x)[0]))