Skip the headers when editing a csv file using Python

Question

Your reader variable is an iterable, by looping over it you retrieve the rows.

To make it skip one item before your loop, simply call next(reader, None) and ignore the return value.

You can also simplify your code a little; use the opened files as context managers to have them closed automatically:

with open("tmob_notcleaned.csv", "rb") as infile, open("tmob_cleaned.csv", "wb") as outfile:
   reader = csv.reader(infile)
   next(reader, None)  # skip the headers
   writer = csv.writer(outfile)
   for row in reader:
       # process each row
       writer.writerow(row)

# no need to close, the files are closed automatically when you get to this point.

If you wanted to write the header to the output file unprocessed, that's easy too, pass the output of next() to writer.writerow():

headers = next(reader, None)  # returns the headers or `None` if the input is empty
if headers:
    writer.writerow(headers)

Another way of solving this is to use the DictReader class, which "skips" the header row and uses it to allowed named indexing.

Given "foo.csv" as follows:

FirstColumn,SecondColumn
asdf,1234
qwer,5678

Use DictReader like this:

import csv
with open('foo.csv') as f:
    reader = csv.DictReader(f, delimiter=',')
    for row in reader:
        print(row['FirstColumn'])  # Access by column header instead of column number
        print(row['SecondColumn'])

Doing row=1 won't change anything, because you'll just overwrite that with the results of the loop.

You want to do next(reader) to skip one row.

Simply iterate one time with next()

with open(filename) as file:

    csvreaded = csv.reader(file)
    header = next(csvreaded)

    for row in csvreaded:
        empty_list.append(row) #your csv list without header  

or use [1:] at the end of reader object

with open(filename) as file:

    csvreaded = csv.reader(file)
    header = next(csvreaded)

    for row in csvreaded[1:]:
        empty_list.append(row) #your csv list without header