Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

How does the main() method work in C?

Tags:

c++

c

I know there are two different signatures to write the main method -

int main() {    //Code } 

or for handling command line argument, we write it as-

int main(int argc, char * argv[]) {    //code } 

In C++ I know we can overload a method, but in C how does the compiler handle these two different signatures of main function?

like image 525
ritesh Avatar asked Oct 17 '13 06:10

ritesh


People also ask

What does the main () do?

main() is the known entry point when the run-time code is ready to start executing your program.

What is main () called in C?

In 'C' you can even call the main() function, which is also known as the "called function" of one program in another program, which is called "calling function"; by including the header file into the calling function.

Is there a main method in C?

In C, the "main" function is treated the same as every function, it has a return type (and in some cases accepts inputs via parameters). The only difference is that the main function is "called" by the operating system when the user runs the program.

What would happen if main () main (); is executed?

Well,you can call a main() within the main() function ,but you should have a condition that does not call the main() function to terminate the program. Otherwise,the program will never return and run infinitely. It will cause a stack overflow when the stack space is used up.


2 Answers

Some of the features of the C language started out as hacks which just happened to work.

Multiple signatures for main, as well as variable-length argument lists, is one of those features.

Programmers noticed that they can pass extra arguments to a function, and nothing bad happens with their given compiler.

This is the case if the calling conventions are such that:

  1. The calling function cleans up the arguments.
  2. The leftmost arguments are closer to the top of the stack, or to the base of the stack frame, so that spurious arguments do not invalidate the addressing.

One set of calling conventions which obeys these rules is stack-based parameter passing whereby the caller pops the arguments, and they are pushed right to left:

 ;; pseudo-assembly-language  ;; main(argc, argv, envp); call   push envp  ;; rightmost argument  push argv  ;;   push argc  ;; leftmost argument ends up on top of stack   call main   pop        ;; caller cleans up     pop  pop 

In compilers where this type of calling convention is the case, nothing special need to be done to support the two kinds of main, or even additional kinds. main can be a function of no arguments, in which case it is oblivious to the items that were pushed onto the stack. If it's a function of two arguments, then it finds argc and argv as the two topmost stack items. If it's a platform-specific three-argument variant with an environment pointer (a common extension), that will work too: it will find that third argument as the third element from the top of the stack.

And so a fixed call works for all cases, allowing a single, fixed start-up module to be linked to the program. That module could be written in C, as a function resembling this:

/* I'm adding envp to show that even a popular platform-specific variant    can be handled. */ extern int main(int argc, char **argv, char **envp);  void __start(void) {   /* This is the real startup function for the executable.      It performs a bunch of library initialization. */    /* ... */    /* And then: */   exit(main(argc_from_somewhere, argv_from_somewhere, envp_from_somewhere)); } 

In other words, this start module just calls a three-argument main, always. If main takes no arguments, or only int, char **, it happens to work fine, as well as if it takes no arguments, due to the calling conventions.

If you were to do this kind of thing in your program, it would be nonportable and considered undefined behavior by ISO C: declaring and calling a function in one manner, and defining it in another. But a compiler's startup trick does not have to be portable; it is not guided by the rules for portable programs.

But suppose that the calling conventions are such that it cannot work this way. In that case, the compiler has to treat main specially. When it notices that it's compiling the main function, it can generate code which is compatible with, say, a three argument call.

That is to say, you write this:

int main(void) {    /* ... */ } 

But when the compiler sees it, it essentially performs a code transformation so that the function which it compiles looks more like this:

int main(int __argc_ignore, char **__argv_ignore, char **__envp_ignore) {    /* ... */ } 

except that the names __argc_ignore don't literally exist. No such names are introduced into your scope, and there won't be any warning about unused arguments. The code transformation causes the compiler to emit code with the correct linkage which knows that it has to clean up three arguments.

Another implementation strategy is for the compiler or perhaps linker to custom-generate the __start function (or whatever it is called), or at least select one from several pre-compiled alternatives. Information could be stored in the object file about which of the supported forms of main is being used. The linker can look at this info, and select the correct version of the start-up module which contains a call to main which is compatible with the program's definition. C implementations usually have only a small number of supported forms of main so this approach is feasible.

Compilers for the C99 language always have to treat main specially, to some extent, to support the hack that if the function terminates without a return statement, the behavior is as if return 0 were executed. This, again, can be treated by a code transformation. The compiler notices that a function called main is being compiled. Then it checks whether the end of the body is potentially reachable. If so, it inserts a return 0;

like image 167
Kaz Avatar answered Sep 21 '22 06:09

Kaz


There is NO overloading of main even in C++. Main function is the entry point for a program and only a single definition should exist.

For Standard C

For a hosted environment (that's the normal one), the C99 standard says:

5.1.2.2.1 Program startup

The function called at program startup is named main. The implementation declares no prototype for this function. It shall be defined with a return type of int and with no parameters:

int main(void) { /* ... */ } 

or with two parameters (referred to here as argc and argv, though any names may be used, as they are local to the function in which they are declared):

int main(int argc, char *argv[]) { /* ... */ } 

or equivalent;9) or in some other implementation-defined manner.

9) Thus, int can be replaced by a typedef name defined as int, or the type of argv can be written as char **argv, and so on.

For standard C++:

3.6.1 Main function [basic.start.main]

1 A program shall contain a global function called main, which is the designated start of the program. [...]

2 An implementation shall not predefine the main function. This function shall not be overloaded. It shall have a return type of type int, but otherwise its type is implementation defined. All implementations shall allow both of the following definitions of main:

int main() { /* ... */ } 

and

int main(int argc, char* argv[]) { /* ... */ } 

The C++ standard explicitly says "It [the main function] shall have a return type of type int, but otherwise its type is implementation defined", and requires the same two signatures as the C standard.

In a hosted environment (A C environment which also supports the C libraries) - the Operating System calls main.

In a non-hosted environment (One intended for embedded applications) you can always change the entry point (or exit) of your program using the pre-processor directives like

#pragma startup [priority] #pragma exit [priority] 

Where priority is an optional integral number.

Pragma startup executes the function before the main (priority-wise) and pragma exit executes the function after the main function. If there is more than one startup directive then priority decides which will execute first.

like image 41
Sadique Avatar answered Sep 22 '22 06:09

Sadique