How do you use Django URL namespaces?

Question

I'm trying to get the hang of Django URL namespaces. But I can't find any examples or documentation.

Here is what I have tried.

urls.py:

from django.conf.urls.defaults import *  urlpatterns = patterns('',     (r'^foo/', include('sub_urls', namespace='foo', app_name='foo')),     (r'^bar/', include('sub_urls', namespace='bar', app_name='bar')),             ) 

sub_urls.py:

from django.conf.urls.defaults import patterns, url from views import view1  urlpatterns = patterns('views',     url(r'^(?P<view_id>\d+)/$', view1, name='view1') ) 

views.py:

from django.shortcuts import render_to_response  def view1(request, view_id):     return render_to_response('view1.html', locals()) 

In view1.html, {% url foo:view1 3 %} outputs /foo/3, and {% url bar:view1 3 %} outputs /bar/3. This holds true whether I browse to /foo/X or /bar/X.

What I want is to be able to browse to /foo/X or /bar/X, and have {% url view1 3 %} output either /foo/3 or /bar/3, respectively.

Answer 1

There seems to be no direct way to do it. I would use a similiar solution as you introduced using a template tag, though I found a more generic way. I used the fact that you can pass optional parameters in your url conf, so you can keep track of the namespace:

#urls.py from django.conf.urls import defaults  urlpatterns = defaults.patterns('',     defaults.url(r'^foo/', include('sub_urls', namespace='foo', app_name='myapp'),      kwargs={'namespace':'foo'}),     defaults.url(r'^bar/', include('sub_urls', namespace='bar', app_name='myapp'),     kwargs={'namespace':'bar'}),       ) 

That also violates the DRY principle, but not much though :)

Then in your view you get the namespace variable (sub_urls.py would be the same):

#views.py from django import shortcuts  def myvew(request, namespace):     context = dict(namespace=namespace)     return shortcuts.render_to_response('mytemplate.html', context) 

Later you just need a simple tag you pass your namespace variable and view name to:

#tags.py from django import template from django.core import urlresolvers  register = template.Library()  def namespace_url(namespace, view_name):    return urlresolvers.reverse('%s:%s' % (namespace, view_name, args=args, kwargs=kwargs))) register.simple_tag(namespace_url) 

and use it in the template (make sure to pass your view name as a string, and not as a template variable):

<!-- mytemplate.html --> {% load tags %} {% namespace_url namespace "view1"%} 

Thanks for your hint btw.. I was looking for sth. like this.