How do you make std::shared_ptr not call delete()

Question

I have functions that take in std::shared_ptr as an argument so I am forced to use std::shared_ptr, but the object I am passing to the function is not dynamically allocated. How do I wrap the object in std::shared_ptr and have std::shared_ptr not call delete on it.

Answer 1

Specify a no-op deleter when creating the shared pointer. E.g. like this:

void null_deleter(MyType *) {}  int main() {   MyType t;   nasty_function(std::shared_ptr<MyType>(&t, &null_deleter)); } 

Answer 2

MyType t; nasty_function(std::shared_ptr<MyType>(&t, [](MyType*){}));