How do you index on a jinja template?

Question

I'm passing 3 lists to my jinja template through my python file.

list1 = [1,2,3,4] list2 = ['a','b','c','d'] list3 = [5,6,7,8] 

All these values correspond with eachother, so 1 matches with 'a' and 5, 2 with 'b' and 6, etc.

In my template I'm printing them out on the same line. How do I do numerical indexing to print them out? As so

1 a 5 2 b 6 3 c 7 

The only thing I know is directly accessing the object through the loop like

 {%for item in list%}     {{item}} 

Answer 1

If you really want the index, you could just loop on one of the variables and then uses Jinja's loop.index0 feature (returns the current index of the loop starting at 0 (loop.index does the same thing, starting at 1)

For example:

{% for item in list1 %}      {{ item }}     {{ list2[loop.index0] }}     {{ list3[loop.index0] }}  {% endfor %} 

This assumes your lists are all asserted to be the same length before setting the template, or you'll encounter problems.

Answer 2

Two ways:

1. In your code that calls Jinja simply zip your lists:

   data = zip(list1, list2, list3) # data is now a list of tuples # [(1, 'a', 5), (2, 'b', 6), etc.] 

   Then, in your template you can simply loop over the nested rows:

   {# your_template.jinja #} <table> {% for row in data %}     <tr>     {% for cell in row %}         <td>{{ cell }}</td>     {% endfor %}     </tr> {% endfor %} </table> 

2. As an alternate, if you only want to use Jinja you can use the special loop variable:

   <table> {% for cell in list1 %}     <tr>         <td>{{ list1[loop.index0] }}</td>         <td>{{ list2[loop.index0] }}</td>         <td>{{ list3[loop.index0] }}</td>     </tr> {% endfor %} </table>