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For example, if you have n lists of bools of the same length, then elementwise boolean AND should return another list of that length that has True in those positions where all the input lists have True, and False everywhere else.
It's pretty easy to write, i just would prefer to use a builtin if one exists (for the sake of standardization/readability).
Here's an implementation of elementwise AND:
def eAnd(*args): return [all(tuple) for tuple in zip(*args)] example usage:
>>> eAnd([True, False, True, False, True], [True, True, False, False, True], [True, True, False, False, True]) [True, False, False, False, True] 
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A boolean list ("blist") is a list that has no holes and contains only true and false .
Boolean operators are specific words and symbols that you can use to expand or narrow your search parameters when using a database or search engine. The most common Boolean operators are AND, OR, NOT or AND NOT, quotation marks “”, parentheses (), and asterisks *.
There are three logical operators that are used to compare values. They evaluate expressions down to Boolean values, returning either True or False . These operators are and , or , and not and are defined in the table below.
However, and and or are so useful that all programming languages have both. There are sixteen possible two-input Boolean operators. Except for and and or , they are rarely needed in practice. Because of this, True , False , not , and , and or are the only built-in Python Boolean operators.
There is not a built-in way to do this. Generally speaking, list comprehensions and the like are how you do elementwise operations in Python.
Numpy does provide this (using &, for technical limitations) in its array type. Numpy arrays usually perform operations elementwise.
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Try:
[ x&y for (x,y) in zip(list_a, list_b)] If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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