#include <stdio.h> int main() { unsigned long long int num = 285212672; //FYI: fits in 29 bits int normalInt = 5; printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\n", sizeof(num), num, normalInt); return 0; }
Output:
My number is 8 bytes wide and its value is 285212672l. A normal number is 0.
I assume this unexpected result is from printing the unsigned long long int
. How do you printf()
an unsigned long long int
?
Use the format specifier “ %lu” . This format specifier is used to output an Unsigned long int.
Use the ll (el-el) long-long modifier with the u (unsigned) conversion. (Works in windows, GNU).
printf("%llu", 285212672);
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