How do you enumerate over an array of blocks?

Question

self.myArray = @[ [^{ NSLog(@"a"); } copy],
                  [^{ NSLog(@"b"); } copy]];

... Later ....

[self.myArray enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
    // This syntax is wrong, but I hope you get my intention
    void (^) (void) block = obj;  
    block();
}];

How do you cast out the block when enumerating over it? (Bonus if you can do it without a typedef)

Answer 1

[self.myArray enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
    void (^block)() = obj;  
    block();
}];

Or directly in the argument list:

[self.myArray enumerateObjectsUsingBlock:^(void (^block)(), NSUInteger idx, BOOL *stop) {
    block();
}];

Answer 2

This should work:

void (^block )(void) = obj;