How do you check the success of open (file) in Perl?

Question

The following (not very Perl-ish) code

#!/usr/bin/perl

if (! -e "mydir/")
{
  print "directory doesn't exist.\n";
}
open (my $fh, ">", "mydir/file.txt");
if ($fh)
{
  print "file opened.\n";
  print $fh;
  print $fh "some text\n" or die "failed to write to file.\n";
  close ($fh);
}
else
{
  print "failed to open file.\n";
}

produces the output such as this

directory doesn't exist.
file opened.
failed to write to file.
GLOB(0x...some-hex-digits...)

Why is $fh not equivalent to false following the open call? As mydir/ does not exist, I'd expect the attempt to open the file to fail.

I get similar results if the directory and file exist, but the file is read-only.

I've tried this with Perl 5.10.1 on Windows 7 x64, and with Perl 5.10.0 on Fedora-11 Linux.

I'm guessing my file handle test is wrong. I've tried Googling this without luck. I expect it's something obvious, but any hints or links would be much appreciated.

Thanks, Rob.

Answer 1

$fh isn't being set to a zero-ish value, it is being set to a GLOB as your code shows. This is different from what open returns which is why the idiom is

open(...) or die ... ;

or

unless(open(...)) {
    ...
}