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How can variadic functions like printf find out the number of arguments they got?
The amount of arguments obviously isn't passed as a (hidden) parameter (see a call to printf in asm example here).
What's the trick?
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Variadic functions are functions that can take a variable number of arguments. In C programming, a variadic function adds flexibility to the program. It takes one fixed argument and then any number of arguments can be passed.
Variable length argument is a feature that allows a function to receive any number of arguments.
Variable Arguments (Varargs) in Java is a method that takes a variable number of arguments. Variable Arguments in Java simplifies the creation of methods that need to take a variable number of arguments.
The trick is that you tell them somehow else. For printf you have to supply a format string which even contains type information (which might be incorrect though). The way to supply this information is mainly user-contract and often error-prone.
As for calling conventions: Usually the arguments are pushed onto the stack from left to right and then the backjump address at last. The calling routine clears the stack. So there is no technical need for the called routine to know the number of parameters.
EDIT: In C++0x there is a safe way (even typesafe!) to call variadic functions!
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