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How do I use the ngCordova sqlite service and the Cordova-SQLitePlugin with Ionic Framework?

I have been trying to incorperate sqlite into a simple Ionic app and this is the process I have been following:

 ionic start myApp sidemenu

Then I install the sqlite plugin:

ionic plugin add https://github.com/brodysoft/Cordova-SQLitePlugin

and ngCordova

bower install ngCordova

this gave me the following options: Unable to find a suitable version for angular, please choose one: 1) angular#1.2.0 which resolved to 1.2.0 and is required by ngCordova#0.1.4-alpha 2) angular#>= 1.0.8 which resolved to 1.2.0 and is required by angular-ui-router#0.2.10 3) angular#1.2.25 which resolved to 1.2.25 and is required by angular-animate#1.2.25, angular-sanitize#1.2.25 4) angular#~1.2.17 which resolved to 1.2.25 and is required by ionic#1.0.0-beta.13Prefix the choice with ! to persist it to bower.json

I picked option 3) and I included the scripts in the file as follows:

<script src="lib/ionic/js/ionic.bundle.js"></script>
<script src="lib/ngCordova/dist/ng-cordova.js"></script>
<script src="cordova.js"></script>
<script src="js/app.js"></script>
<script src="js/controllers.js"></script>

I then added a controller to the search view:

.controller('SearchCtrl', function ($scope, $cordovaSQLite){
  console.log('Test');
   var db = $cordovaSQLite.openDB({ name: "my.db" });

        // for opening a background db:
        var db = $cordovaSQLite.openDB({ name: "my.db", bgType: 1 });

        $scope.execute = function() {
          console.log('Test');
          var query = "INSERT INTO test_table (data, data_num) VALUES (?,?)";
          $cordovaSQLite.execute(db, query, ["test", 100]).then(function(res) {
            console.log("insertId: " + res.insertId);
          }, function (err) {
            console.error(err);
          });
     };
})

This caused the error:

> TypeError: Cannot read property 'openDatabase' of undefined
>     at Object.openDB  (http://localhost:8100/lib/ngCordova/dist/ng-cordova.js:2467:36) 

Next I tried manually including the SQLitePlugin.js by: copying from plugins/com.brodysoft.sqlitePlugin/www to main www/ and adding it to the index.html page

I tried including before everything:

 <script src="SQLitePlugin.js"></script>
<script src="lib/ionic/js/ionic.bundle.js"></script>
<script src="lib/ngCordova/dist/ng-cordova.js"></script>
<script src="cordova.js"></script>
<script src="js/app.js"></script>
<script src="js/controllers.js"></script>

I get Error ReferenceError: cordova is not defined so I then tried including it after the cordova.js script but still get the same error

would really appreciate the help in case it is relevant, these are the current versions of Cordova and ionic I am using:

ionic --version  1.2.5
cordova --version 3.5.0-0.2.7

and this is the generated bower.json

{
  "name": "myApp",
  "private": "true",
  "devDependencies": {
    "ionic": "driftyco/ionic-bower#1.0.0-beta.13"
  }
}

and my package.json:

{
  "name": "myapp",
  "version": "1.0.0",
  "description": "myApp: An Ionic project",
  "dependencies": {
    "gulp": "^3.5.6",
    "gulp-sass": "^0.7.1",
    "gulp-concat": "^2.2.0",
    "gulp-minify-css": "^0.3.0",
    "gulp-rename": "^1.2.0"
  },
  "devDependencies": {
    "bower": "^1.3.3",
    "gulp-util": "^2.2.14",
    "shelljs": "^0.3.0"
  }
}
like image 914
jonnie Avatar asked Sep 29 '14 13:09

jonnie


2 Answers

If someone still got an error when trying to run it in a browser, try this one:

if (window.cordova) {
      db = $cordovaSQLite.openDB({ name: "my.db" }); //device
    }else{
      db = window.openDatabase("my.db", '1', 'my', 1024 * 1024 * 100); // browser
    }
like image 137
junior Avatar answered Oct 22 '22 16:10

junior


So Turns out that it is because Cordova is platform specific and doesn't work when you run ionic serve

I was able to run the same code on an android device with out issue when I built and deployed.

Update

you can replace the cordova plugin with window to use the websql databases so instead of sqlitePlugin.openDatabase() you can use window.openDatabase()

like image 43
jonnie Avatar answered Oct 22 '22 18:10

jonnie