An interface can contain declarations of methods, properties, indexers, and events. However, it cannot contain fields, auto-implemented properties.
Beginning with C# 8.0, an interface may define a default implementation for members, including properties. Defining a default implementation for a property in an interface is rare because interfaces may not define instance data fields.
You just specify that there is a property with a getter and a setter, whatever they will do. In the class, you actually implement them. The shortest way to do this is using this { get; set; } syntax. The compiler will create a field and generate the getter and setter implementation for it.
Yes, An interface should define properties when it really in need. Please suppose that. There is a IUser interface that has defined a property "Name" then you can use it without worry about if the object didn't implement the property.
I think the class you are looking for is System.Reflection.InterfaceMapping.
Type ifaceType = typeof(TempInterface);
Type tempType = typeof(TempClass);
InterfaceMapping map = tempType.GetInterfaceMap(ifaceType);
for (int i = 0; i < map.InterfaceMethods.Length; i++)
{
MethodInfo ifaceMethod = map.InterfaceMethods[i];
MethodInfo targetMethod = map.TargetMethods[i];
Debug.WriteLine(String.Format("{0} maps to {1}", ifaceMethod, targetMethod));
}
The property getter and setter of an explicitly implemented interface property has an unusual attribute. It's IsFinal property is True, even when it is not a member of a sealed class. Try this code to verify my assertion:
foreach (AssemblyName name in Assembly.GetEntryAssembly().GetReferencedAssemblies()) {
Assembly asm = Assembly.Load(name);
foreach (Type t in asm.GetTypes()) {
if (t.IsAbstract) continue;
foreach (MethodInfo mi in t.GetMethods(BindingFlags.NonPublic | BindingFlags.Instance)) {
int dot = mi.Name.LastIndexOf('.');
string s = mi.Name.Substring(dot + 1);
if (!s.StartsWith("get_") && !s.StartsWith("set_")) continue;
if (mi.IsFinal)
Console.WriteLine(mi.Name);
}
}
}
Here's a modified solution based on the implementation given in this blog post:
var explicitProperties =
from prop in typeof(TempClass).GetProperties(
BindingFlags.NonPublic | BindingFlags.Instance | BindingFlags.DeclaredOnly)
let getAccessor = prop.GetGetMethod(true)
where getAccessor.IsFinal && getAccessor.IsPrivate
select prop;
foreach (var p in explicitProperties)
Console.WriteLine(p.Name);
Building on the answer by MrKurt:
var targetMethods =
from iface in typeof(TempClass).GetInterfaces()
from method in typeof(TempClass).GetInterfaceMap(iface).TargetMethods
select method;
var explicitProps =
from prop in typeof(TempClass).GetProperties(BindingFlags.Instance |
BindingFlags.NonPublic)
where targetMethods.Contains(prop.GetGetMethod(true)) ||
targetMethods.Contains(prop.GetSetMethod(true))
select prop;
I had to modify Jacob Carpenter's answer but it works nicely. nobugz's also works but Jacobs is more compact.
var explicitProperties =
from method in typeof(TempClass).GetMethods(BindingFlags.NonPublic | BindingFlags.Instance)
where method.IsFinal && method.IsPrivate
select method;
A simple helper class that could help:
public class InterfacesPropertiesMap
{
private readonly Dictionary<Type, PropertyInfo[]> map;
public InterfacesPropertiesMap(Type type)
{
this.Interfaces = type.GetInterfaces();
var properties = type.GetProperties(BindingFlags.NonPublic | BindingFlags.Instance | BindingFlags.Public);
this.map = new Dictionary<Type, PropertyInfo[]>(this.Interfaces.Length);
foreach (var intr in this.Interfaces)
{
var interfaceMap = type.GetInterfaceMap(intr);
this.map.Add(intr, properties.Where(p => interfaceMap.TargetMethods
.Any(t => t == p.GetGetMethod(true) ||
t == p.GetSetMethod(true)))
.Distinct().ToArray());
}
}
public Type[] Interfaces { get; private set; }
public PropertyInfo[] this[Type interfaceType]
{
get { return this.map[interfaceType]; }
}
}
You'll get properties for each interface, even explicitly implemented.
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