I have a Python module which uses some resources in a subdirectory of the module directory. After searching around on stack overflow and finding related answers, I managed to direct the module to the resources by using something like
import os os.path.join(os.path.dirname(__file__), 'fonts/myfont.ttf')
This works fine when I call the module from elsewhere, but it breaks when I call the module after changing the current working directory. The problem is that the contents of __file__
are a relative path, which doesn't take into account the fact that I changed the directory:
>>> mymodule.__file__ 'mymodule/__init__.pyc' >>> os.chdir('..') >>> mymodule.__file__ 'mymodule/__init__.pyc'
How can I encode the absolute path in __file__
, or barring that, how can I access my resources in the module no matter what the current working directory is? Thanks!
path. relpath() method in Python is used to get a relative filepath to the given path either from the current working directory or from the given directory. Note: This method only computes the relative path.
In Pathlib, the Path. cwd() function is used to get the current working directory and / operator is used in place of os. path. join to combine parts of the path into a compound path object. The function nesting pattern in the os.
Store the absolute path to the module directory at the very beginning of the module:
package_directory = os.path.dirname(os.path.abspath(__file__))
Afterwards, load your resources based on this package_directory
:
font_file = os.path.join(package_directory, 'fonts', 'myfont.ttf')
And after all, do not modify of process-wide resources like the current working directory. There is never a real need to change the working directory in a well-written program, consequently avoid os.chdir()
.
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