Trying to use open(filename, 'w' ) gives IOError: [Errno 2] No such file or directory if directory doesn't exist

Question

I am trying to create and write to a text file using Python. I have searched and cannot find a solution/reason for this error.

Here's the code that doesn't work:

afile = 'D:\\temp\\test.txt' outFile = open(afile, 'w' ) outFile.write('Test.') outFile.close()  # Error: 2 # Traceback (most recent call last): #   File "<maya console>", line 1, in <module> # IOError: [Errno 2] No such file or directory: 'D:\\temp\\test.txt' # 

Most answers I found related to the slashes in the path, so...

I tried 'D:/temp/test.txt' and got an error. I tried r'D:\temp\test.txt' and got an error. 

When I try to create a file at the root of D:/ I have success.

'D:/test.txt' works. 'D:\\test.txt' works. r'D:\test.txt' works. 

It seems that I can't create the directory path I would like while trying to create the file. What is the correct method for creating files at a specific path with Python on Windows(7)? Am I misunderstanding what open() can do? Does it create directories if they don't exist or do I need to explicitly create the directory path before I use open() in 'write' mode to create a file?

Answer 1

You are correct in surmising that the parent directory for the file must exist in order for open to succeed. The simple way to deal with this is to make a call to os.makedirs.

From the documentation:

os.makedirs(path[, mode])

Recursive directory creation function. Like mkdir(), but makes all intermediate-level directories needed to contain the leaf directory.

So your code might run something like this:

filename = ... dirname = os.path.dirname(filename) if not os.path.exists(dirname):     os.makedirs(dirname) with open(filename, 'w'):     ... 

Answer 2

If you try to create a file in a directory that doesn't exist, you will get that error.

You need to ensure the directory exists first. You can do that with os.makedirs() as per this answer.