How do I unwrap an Optional when pattern matching tuples in Swift?

Question

In Swift, there's a common if let pattern used to unwrap optionals:

if let value = optional {
    print("value is now unwrapped: \(value)")
}

I'm currently doing this kind of pattern matching, but with tuples in a switch case, where both params are optionals:

//url is optional here
switch (year, url) {
    case (1990...2015, let unwrappedUrl):
        print("Current year is \(year), go to: \(unwrappedUrl)")
}       

However, this prints:

"Current year is 2000, go to Optional(www.google.com)"

Is there a way I can unwrap my optional and pattern match only if it's not nil? Currently my workaround is this:

switch (year, url) {
    case (1990...2015, let unwrappedUrl) where unwrappedUrl != nil:
        print("Current year is \(year), go to: \(unwrappedUrl!)")
}       

Answer 1

You can use the x? pattern:

case (1990...2015, let unwrappedUrl?):
    print("Current year is \(year), go to: \(unwrappedUrl)")

x? is just a shortcut for .some(x), so this is equivalent to

case (1990...2015, let .some(unwrappedUrl)):
    print("Current year is \(year), go to: \(unwrappedUrl)")

Answer 2

with a switch case you can unwrap (when needed) and also evaluate the unwrapped values (by using where) in the same case.

Like this:

let a: Bool? = nil
let b: Bool? = true

switch (a, b) {
case let (unwrappedA?, unwrappedB?) where unwrappedA || unwrappedB:
  print ("A and B are not nil, either A or B is true")
case let (unwrappedA?, nil) where unwrappedA:
  print ("A is True, B is nil")
case let (nil, unwrappedB?) where unwrappedB:
  print ("A is nil, B is True")
default:
  print("default case")
}