I have a python list [1,2,,4,5,6]
. What is the best method for testing for the missing, or null
, list element? I am currently performing a if element != ''
but I think there is a built-in test to perform such a thing, or am I wrong?
You can use the len() function with the comparison operator and compare the result with 0 to check if the list is empty. What is this? If the list is empty, then the If statement will be executed. This is how you can use the len() function with the comparison operator to check if the list is empty or not in python.
Checking empty list using len() Function. The len() function is used to find the number of elements in the list. So, to check if the list is empty or not using len(), we can pass the empty list to the len() function, and if we get 0, that means the list is empty.
We can use the in-built python List method, count(), to check if the passed element exists in the List. If the passed element exists in the List, the count() method will show the number of times it occurs in the entire list. If it is a non-zero positive number, it means an element exists in the List.
Pythonic ways for checking for None
or null
are:
if element:
# This is not null
if not element:
# This is null
There is a very detailed answer on the difference between if not x
and if x == None
.
Combining the comment and the other answers:
Python treats the following as False
source:
None
False
0
, 0L
, 0.0
, 0j
''
, ()
, []
{}
__nonzero__()
or __len__()
method, when that method returns the integer zero
or bool value False
All other values are considered to be True
.
If you are indeed checking if None
is present in your list ([1,2,None,4,5,6]
) then @Poke 's answer is right:
>>> lst = [1, 2, None, 4, 5, 6]
>>> None in lst
True
If you are wanting to check that the element is only None
then @esauro is correct in the comments:
>>> lst = [1, 2, None, 4, 5, 6]
>>> for x in lst:
... if not x:
... print(x)
None
But if your lst
contains 0
(lst = [0, 1, 2, 4, 5, 6]) then your output will be 0
.
The only way you could get round this would be to explicitly check if element is None
or if element is not None
.
If your list is [1, 2, None, 4, 5, 6]
then you can just check None in lst
, e.g.:
>>> lst = [1, 2, None, 4, 5, 6]
>>> None in lst
True
Similarly, if you have some other value that represents a “missing” entry, you can just check whatever in lst
.
I have a python list [1,2,,4,5,6]. What is the best method for testing for the missing, or null, list element?
If you just want to know if the list contains a falsey value (that's the best equivalent for missing or null in Python), you can do this:
>>> all(x for x in [1,2,3,4,5])
True
>>> all(x for x in [1,2,'',4,5])
False
>>> all(x for x in [1,2,None,4,5])
False
If you want to know if a specific value exists that matches some condition:
all(x%2 for x in [1,2,3,4,5,7])
This will be true if the list contains all even numbers.
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