How to get Facebook access token using Python library?

Question

I've found this Library it seems it is the official one, then found this, but everytime i find an answer the half of it are links to Facebook API Documentation which talks about Javascript or PHP and how to extract it from links!

How do i make it on simple python script?

NB: what i realy dont understand, why using a library and cant extract token if we can use urllib and regex to extract informations?

Answer 1

Not sure if this helps anyone, but I was able to get an oauth_access_token by following this code.

from facepy import utils
app_id = 134134134134 # must be integer
app_secret = "XXXXXXXXXXXXXXXXXX" 
oath_access_token = utils.get_application_access_token(app_id, app_secret)

Hope this helps.

Answer 2

Javascript and PHP can be used as web development languages. You need a web front end for the user to grant permission so that you can obtain the access token.

Rephrased: You cannot obtain the access token programmatically, there must be manual user interaction

In Python it will involve setting up a web server, for example a script to update feed using facepy

import web
from facepy import GraphAPI
from urlparse import parse_qs

url = ('/', 'index')

app_id = "YOUR_APP_ID"
app_secret = "APP_SECRET"
post_login_url = "http://0.0.0.0:8080/"

user_data = web.input(code=None)

if not user_data.code:
    dialog_url = ( "http://www.facebook.com/dialog/oauth?" +
                               "client_id=" + app_id +
                               "&redirect_uri=" + post_login_url +
                               "&scope=publish_stream" )

    return "<script>top.location.href='" + dialog_url + "'</script>"
else:
    graph = GraphAPI()
    response = graph.get(
        path='oauth/access_token',
        client_id=app_id,
        client_secret=app_secret,
        redirect_uri=post_login_url,
        code=code
    )
    data = parse_qs(response)
    graph = GraphAPI(data['access_token'][0])
    graph.post(path = 'me/feed', message = 'Your message here')

Answer 3

here is a Gist i tried to make using Tornado since the answer uses web.py

https://gist.github.com/abdelouahabb/5647185