How do I sort a Set to a List in Java?

Question

The answer provided by the OP is not the best. It is inefficient, as it creates a new List and an unnecessary new array. Also, it raises "unchecked" warnings because of the type safety issues around generic arrays.

Instead, use something like this:

public static
<T extends Comparable<? super T>> List<T> asSortedList(Collection<T> c) {
  List<T> list = new ArrayList<T>(c);
  java.util.Collections.sort(list);
  return list;
}

Here's a usage example:

Map<Integer, String> map = new HashMap<Integer, String>();
/* Add entries to the map. */
...
/* Now get a sorted list of the *values* in the map. */
Collection<String> unsorted = map.values();
List<String> sorted = Util.asSortedList(unsorted);

Sorted set:

return new TreeSet(setIWantSorted);

or:

return new ArrayList(new TreeSet(setIWantSorted));

Here's how you can do it with Java 8's Streams:

mySet.stream().sorted().collect(Collectors.toList());

or with a custom comparator:

mySet.stream().sorted(myComparator).collect(Collectors.toList());

List myList = new ArrayList(collection);
Collections.sort(myList);

… should do the trick however. Add flavour with Generics where applicable.