How do I slice a string by characters in Python? [duplicate]

Question

There is a string with one or more characters. I want to slice the list so that the adjoining same characters are in the same element. For example:

'a' -> ['a']
'abbbcc' -> ['a', 'bbb', 'cc']
'abcabc' -> ['a', 'b', 'c', 'a', 'b', 'c']

How do I make this in Python?

Answer 1

It can be achieved with re.finditer():

import re
s = 'aabccdd'
print([m.group(0) for m in re.finditer(r"(\w)\1*", s)])
#['aa', 'b', 'cc', 'dd']

Answer 2

Without any modules and using a for loop it can also be done in an interesting way:

l = []
str = "aabccc"
s = str[0]
for c in str[1:]:

    if (c != s[-1]):
        l.append(s)
        s = c
    else:
        s = s + c
l.append(s)
print(l)

Answer 3

Use itertools.groupby:

from itertools import groupby

s = 'abccbba'

print([''.join(v) for _, v in groupby(s)])
# ['a', 'b', 'cc', 'bb', 'a']