Pass all arguments of a function to another function

Question

I want to have a class that I can create subclasses of that has a print function that only prints on a particular condition.

Here's basically what I'm trying to do:

class ClassWithPrintFunctionAndReallyBadName:
    ...
    def print(self, *args):
        if self.condition:
            print(*args)

This works already except for the fact that there are arguments that have to be explicitly stated with the default print function, such as end (example: print('Hello, world!', end='')). How can I make my new class's print function accept arguments such as end='' and pass them to the default print?

Answer 1

The standard way to pass on all arguments is as @JohnColeman suggested in a comment:

class ClassWithPrintFunctionAndReallyBadName:
    ...
    def print(self, *args, **kwargs):
        if self.condition:
            print(*args, **kwargs)

As parameters, *args receives a tuple of the non-keyword (positional) arguments, and **kwargs is a dictionary of the keyword arguments.

When calling a function with * and **, the former tuple is expanded as if the parameters were passed separately and the latter dictionary is expanded as if they were keyword parameters.

Answer 2

class List(list):
    def append_twice(self, *args, **kwargs):
        self.append(*args, **kwargs)
        self.append(*args, **kwargs)

l = List()
l.append_twice("Hello")
print(l) # ['Hello', 'Hello']