How do I search for an executable file using python in linux?

Question

How do I search for an executable file using python in linux? The executable files have no extensions and are in a folder together with files that have different extensions. Thanks

EDIT: What I mean by search is to get the filenames of all the executable files and store them in a list or tuple. Thanks

Answer 1

To do it in Python:

import os
import stat

executable = stat.S_IEXEC | stat.S_IXGRP | stat.S_IXOTH
for filename in os.listdir('.'):
    if os.path.isfile(filename):
        st = os.stat(filename)
        mode = st.st_mode
        if mode & executable:
            print(filename,oct(mode))

Answer 2

If by search you mean to list all the executable files in a directory than use the command from this SuperUser Link.You can use Subprocess module to execute the commands from python code.

import shlex   
executables = shlex.split(r'find /dir/mydir -executable -type f')
output_process = subprocess.Popen(executables,shell=True,stdout=subprocess.PIPE)

Answer 3

Function os.access() is in some cases better than os.stat(), because it check whether the file can be executed by you, according to file owner, group and permissions.

import os

for filename in os.listdir('.'):
    if os.path.isfile(filename) and os.access(filename, os.X_OK):
        print(filename)