How do I run an external file within Gulp?

Question

At the moment I'm using the "gulp-run" plugin to run a .bat file. That plugin has now been deprecated and I'm looking for the best way to execute the .bat now.

Current code:

var gulp = require('gulp');
var run = require('gulp-run');

module.exports = function() {

    run('c:/xxx/xxx/runme.bat').exec();

};

Solution as per @cmrn suggestion:

var exec = require('child_process').exec;
var batchLocation = 'c:/xxx/xxx/runme.bat';
gulp.task('task', function (cb) {
  exec(batchLocation, function (err, stdout, stderr) {
    console.log(stdout);
    console.log(stderr);
    cb(err);
  });
})

Answer 1

If you need to run the script as part of a gulp stream (i.e. in pipe()) you can use gulp-exec. If not, you can just use child_process.exec as described in the gulp-exec README, copied below.

var exec = require('child_process').exec;

gulp.task('task', function (cb) {
  exec('ping localhost', function (err, stdout, stderr) {
    console.log(stdout);
    console.log(stderr);
    cb(err);
  });
})