I am trying to print a queue below. I have tried the idea of creating a temp queue and writing into it then writing it back.
But its not working.
Or what am i missing here?
for(int i = 1; i<myQueue.size(); i++)
{
queue<int> tempQueue;
cout << myQueue.front() << endl;
MytempQueue.push(myQueue.front());
myQueue.pop();
myQueue.push(myTempQueue.back());
}
My queue is queue<int> myQueue;
Essentially i want to print this queue without emptying it... But i am stuck here.
There is no efficient way to do this*. But you can do the following:
For example:
#include <queue>
#include <iostream>
void print_queue(std::queue<int> q)
{
while (!q.empty())
{
std::cout << q.front() << " ";
q.pop();
}
std::cout << std::endl;
}
int main()
{
std::queue<int> q;
for (auto i : {1,2,3,7,4,9,7,2,4}) q.push(i);
print_queue(q);
}
* There's a hack using inheritance. std::queue
has a protected member C
which is the underlying container holding the data. You could inherit from std::queue
and add methods to do the printing using C
. But you have to be fully aware of the implications of inheriting from a type that is not necessarily designed for that.
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