I have a set of data that contains a type, a date, and a value.
I want to group by the type, and for each set of values in each group I want to pick the one with the newest date.
Here is some code that works and gives the correct result, but I want to do it all in one linq query rather than in the iteration. Any ideas how I can achieve the same result as this with purely a linq query...?
var mydata = new List<Item> {
new Item { Type = "A", Date = DateTime.Parse("2016/08/11"), Value = 1 },
new Item { Type = "A", Date = DateTime.Parse("2016/08/12"), Value = 2 },
new Item { Type = "B", Date = DateTime.Parse("2016/08/20"), Value = 3 },
new Item { Type = "A", Date = DateTime.Parse("2016/08/09"), Value = 4 },
new Item { Type = "A", Date = DateTime.Parse("2016/08/08"), Value = 5 },
new Item { Type = "C", Date = DateTime.Parse("2016/08/17"), Value = 6 },
new Item { Type = "B", Date = DateTime.Parse("2016/08/30"), Value = 7 },
new Item { Type = "B", Date = DateTime.Parse("2016/08/18"), Value = 8 },
};
var data = mydata.GroupBy(_ => _.Type);
foreach (var thing in data) {
#region
// How can I remove this section and make it part of the group by query above... ?
var subset = thing.OrderByDescending(_ => _.Date);
var top = subset.First();
#endregion
Console.WriteLine($"{thing.Key} {top.Date.ToString("yyyy-MM-dd")} {top.Value}");
}
Where Item
is defined as:
public class Item {
public string Type {get;set;}
public DateTime Date {get;set;}
public int Value {get;set;}
}
Expected output:
A 2016-08-12 2
B 2016-08-30 7
C 2016-08-17 6
Use select
to get the FirstOrDefault
(or First
- because of the grouping you won't get a null) ordered descending:
var data = mydata.GroupBy(item => item.Type)
.Select(group => group.OrderByDescending(x => x.Date)
.FirstOrDefault())
.ToList();
Or SelectMany
together with Take(1)
var data = mydata.GroupBy(item => item.Type)
.SelectMany(group => group.OrderByDescending(x => x.Date)
.Take(1))
.ToList();
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